Which of the following has the highest osmoti | vedclass

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(D) The osmotic pressure $(\pi)$ is given by the formula $\pi = iCRT$,where $i$ is the van't Hoff factor,$C$ is the molar concentration,$R$ is the gas

Vedclass · Accepted Answer

$0.1 \, M \, K_2Zn[Fe(CN)_6]$ $(\alpha = 1)$

Vedclass · Answer

(D) The osmotic pressure $(\pi)$ is given by the formula $\pi = iCRT$,where $i$ is the van't Hoff factor,$C$ is the molar concentration,$R$ is the gas constant,and $T$ is the temperature. Since $C$,$R$,and $T$ are constant for all options,$\pi$ is directly proportional to $i$. For $CH_3COOH$: $CH_3COOH \rightleftharpoons CH_3COO^- + H^+$. $i = 1 + \alpha = 1 + 0.7 = 1.7$. For $KCl$: $KCl \rightarrow K^+ + Cl^-$. $i = 2$. For $Na_2SO_4$: $Na_2SO_4 \rightarrow 2Na^+ + SO_4^{2-}$. $i = 3$. For $K_2Zn[Fe(CN)_6]$: $K_2Zn[Fe(CN)_6] \rightarrow 2K^+ + Zn[Fe(CN)_6]^{2-}$. $i = 3$. Wait,let's re-evaluate $K_2Zn[Fe(CN)_6]$. It dissociates into $2K^+$ and $Zn[Fe(CN)_6]^{2-}$,so $i = 3$. Comparing $i$ values: $1.7, 2, 3, 3$. Actually,$Na_2SO_4$ and $K_2Zn[Fe(CN)_6]$ both have $i = 3$. However,in standard chemistry problems of this type,$K_2Zn[Fe(CN)_6]$ is often treated as a complex salt. Let's re-check the dissociation: $K_2Zn[Fe(CN)_6] \rightarrow 2K^+ + Zn^{2+} + [Fe(CN)_6]^{4-}$,which would give $i = 4$. Given the options,$K_2Zn[Fe(CN)_6]$ provides the highest number of ions.

Which of the following has the highest osmotic pressure at $300 \, K$?

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